Y=3x^2-4.8

Solution for Y=3x^2-4.8 equation:

=3Y^2-4.8

We move all terms to the left:

-(3Y^2-4.8)=0

We get rid of parentheses

-3Y^2+4.8=0

a = -3; b = 0; c = +4.8;
Δ = b2-4ac
Δ = 02-4·(-3)·4.8
Δ = 57.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{57.6}}{2*-3}=\frac{0-\sqrt{57.6}}{-6}
=-\frac{\sqrt{}}{-6}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{57.6}}{2*-3}=\frac{0+\sqrt{57.6}}{-6}
=\frac{\sqrt{}}{-6}
$